Compound Angle Formulæ |
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MathsDirect |
We want to find a way of handling expressions such as
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You do not need to know how the formulæ are derived, but an explanation is given below, for your interest. To go straight to the rules and examples, click here
| The formula for |
Consider the diagram below.
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The side AB has a length of 1. This
leads to the equation
so, we need to find the lengths BF and FE. |
Let's first look at the triangle ABC,( Note that angle BCA is a right angle.)
| This leads us to |
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| and |
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With a little thought, you can see that the angle FBC must equal
| With a little thought, you can see that the angle FBC must equal |
(Clue: FCA is an alternate (Z) angle.)
Let's update the diagram
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represents a length. We can use these two lengths to calculate BF and FE.
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First consider the triangle BCF
Now consider the triangle ACD
which means that
Therefore we can say that
This is a standard identity and may be quoted
On the next page, a similar identity is derived for the cosine of a compound angle
| Go to Derivation of cos | Go straight the examples | Return to Trig Tutorial Contents |
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